If X=1, Y=3, Z=4 Find The Value Of 3x^2-4y^2+2z^23x 2 −4y 2 +2z 2 . - Testpoint

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if x=1, Y=3, Z=4 find the value of 3x^2-4y^2+2z^23x 2 −4y 2 +2z 2 .

7
6
8
4
None of these

Explanation

Solution :

If x= 2, y = 3, z = 4 then

$3x^2-4y^2+2z^2$

= $3(2)^2-4(3)^2+2(4)^2$

= $\left(3\times4\right)-\left(4\times9\right)+\left(2\times16\right)$

= $12-36+32$

= $44-36$

= $8$

∴ $3x^2-4y^2+2z^2=8$

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