Each of the five persons A, B, C, D and E possesses unequal number (<10) of similar items. A. B and C possess 21 items in all while C, D and E posses 7 items in all. How many items do A and B possess in all?
- 18,
- 17,
- 16,
- Data insufficient
Explanation
B)
As A + B + C = 21 I and C + D + E = 7 II For equation II ‘c’ can take values 1 2 and 4 as 1 + 2 + 4 = 7. For C = 1 A + B + 1 = 21 A + B = 20 Similarly for C = 2 A + B = 21 – 2 = 19 and for C = 4 A + B = 21 – 4 = 17
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