A Man Can Reach A Certain Place In 30 Hours. If He Reduces His Speed By 1|15 Th, He Goes 10 Km Less In That Time. Find His Speed In Km

A man can reach a certain place in 30 hours. If he reduces his speed by 1|15 th, he goes 10 km less in that time. Find his speed in km | hr?

15 km/h
5 km/h
10 km/h
None

Explanation

Distance covered in $30$ hours = $30 x$ km

New speed = $[x - \frac{x}{1 5}] k m / h r = \frac{1 4 x}{1 5} k m / h r$

Distance covered in 30 hours = $\frac{1 4 x}{1 5} \times 30 =$ 28x km Given, $30 x - 28 x = 10 k m$ $\Rightarrow$ $x = 5$ km/hr

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A man can reach a certain place in 30 hours. If he reduces his speed by 1|15 th, he goes 10 km less in that time. Find his speed in km | hr?

Explanation

Distance covered in $30$ hours = $30 x$ km

New speed = $[x - \frac{x}{1 5}] k m / h r = \frac{1 4 x}{1 5} k m / h r$

Distance covered in 30 hours = $\frac{1 4 x}{1 5} \times 30 =$ 28x km Given, $30 x - 28 x = 10 k m$ $\Rightarrow$ $x = 5$ km/hr

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A man can reach a certain place in 30 hours. If he reduces his speed by 1|15 th, he goes 10 km less in that time. Find his speed in km | hr?

Explanation

Distance covered in 30 hours = 30x kmNew speed = [x−15x​]km/hr=1514x​km/hrDistance covered in 30 hours = 1514x​×30= 28x km Given,30x−28x=10km ⇒ x=5km/hr

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Distance covered in $30$ hours = $30 x$ km

New speed = $[x - \frac{x}{1 5}] k m / h r = \frac{1 4 x}{1 5} k m / h r$

Distance covered in 30 hours = $\frac{1 4 x}{1 5} \times 30 =$ 28x km Given, $30 x - 28 x = 10 k m$ $\Rightarrow$ $x = 5$ km/hr