Explanation

Assume cost price = 100

Marked price = 25% above CP:

$$100+25=125$$

Discount = 10% on 125:

$$10\%\text{ of }125=12.5$$

Selling price:

$$125-12.5=112.5$$

Profit

$$112.5 - 100 = 12.5$$

$$Last\; updated\; question\; NS\; on\; 10\; MAY\; 2026$$

Explanation

Let original price = x

Step 1: Apply 25% discount

Discounted price =

$$x-25\%\text{ of }x=0.75x$$

Step 2: Apply tax (55% on discounted price)

Final price =

$$0.75x\times 1.55=1.1625x$$

Given final price = 1260

1.1625x=1260
x=1260​/1.1625=1083.87≈1084

Last updated question NS on 10 MAY 2026

Explanation

Let original number = 100

Step 1: Increase by 12%

$$100+12=112$$

Step 2: Decrease 112 by 12%

12% of 112=13.44
$$112-13.44=98.56$$

Step 3: Compare with original

Original = 100
Final = 98.56

Decrease =

$$100-98.56=1.44$$

Percentage change:

$$1.44\%$$

$$Last\; updated\; question\; NS\; on\; 10\; MAY\; 2026$$

Explanation

Ratio boys : girls = 9 : 11
Total students = 80

Total parts = 9 + 11 = 20

Each part = 80 ÷ 20 = 4

Girls = 11 parts:

$$11\times 4=44$$

$$Last\; updated\; question\; NS\; on\; 10\; MAY\; 2026$$

Explanation

• Actual weight = 900 g
• Charged weight = 1000 g

Profit = 100 g (extra charged)

Profit %=100/900​×100=11.11%

Last updated question by NA on 07 May 2026

Explanation

Step-by-step solution:

• 10% of 20 =$frac{10}{100} times 20 = 2$
• 20% of 10 = 20/100​×10=2

Now add both: 2+2=4

Last updated question by NA on 07 May 2026

Explanation

Step 1: Translate the statement into an equation

“One-fourth of one-third of two-fifths of a number is 15”

1​/4×1/3​×2​/5×x=15

Step 2: Multiply fractions

1×1×2/4×3×5​=2/60​= 1/30​

So,

1/30​x=15

Step 3: Solve for x

$$x=15\times 30=450$$

So, the number is

$$x = 450$$

Step 4: Find 40% of the number

40% of 450= 40/100​×450
$$=0.4\times 450=180$$

Last updated question by NA on 07 May 2026

Explanation

This is a distance problem using the Pythagorean theorem.

A person moves:

• 80 km North
• 60 km West

These form a right triangle.

Distance from starting point:

d=  √(80^2 + 60^2)

=√(6400 + 3600)

= √(10000) 

= 100 km

Last updated question by NS on 2 MAY 2026

Explanation

Assume originally:

• Bought 100 items for Rs.100
  So, Cost Price (CP) per item = Rs.1

Now buys 10% less:

• 10% less than 100 = 90 items
• Still spends Rs.100

So new CP per item:

CP= 100/90​

Now sells 10% more:

• 10% more than 100 = 110 items

Assume selling rate is Rs.1 per item.

So total Selling Price:

$$SP=110\times 1=110$$

Profit:

$$Profit=SP-CP=110-100=10$$

Profit percentage formula:

$$\text{Profit \%}=$$Profit/ Cost Price ​×100

Substitute values:

10/100​×100=10%

That approach looks tempting, but it ignores that buying fewer changes the cost per item. The correct combined effect is:

Profit %=(110/90​−1)×100

$(110/90-1)\times 100$

$$=left(frac{20}{90}right)times100$$$$=22.22$$

$$Last\; updated\; question\; by\; NS\; on\; 2\; MAY\; 2026$$

Explanation

To find a single equivalent discount, we apply successive discounts step by step.
Assume original price = 100
Step 1: 10% discount
100 → 90
Step 2: 20% discount on 90
90 → 72
Step 3: 40% discount on 72
72 → 43.2
Final price = 43.2
Total discount:
100 − 43.2 = 56.8

****

Last updated by NS on 01 MAY 2026