SPSC PHYSICS 25 YEARS PAST PAPERS
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چار آپشن میں سے کسی ایک پر کلک کرنے سے جواب سرخ ہو جائے گا۔
مونوٹومک گیس کی صورت میں آزادی کی ڈگری کیا ہے؟
- 5
- 3
- 1
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
The degrees of freedom refer to the number of independent ways a gas molecule can store energy.
For a monoatomic gas (e.g., noble gases like helium, neon, argon):
- It has only translational motion along the x, y, and z axes.
- There are no rotational or vibrational degrees of freedom.
Thus, the total degrees of freedom for a monoatomic gas is 3 (one for each spatial direction: x, y, and z).
- 3.7 km/s
- 112 km/s
- 11.2 km/s
- None of these
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Explanation
Escape velocity (vₑ) is given by:
vₑ = √(2GM/r)
where:
G = gravitational constant
M = mass of the planet
r = radius of the planet
Given:
M₂ = 1000M₁ (mass of the new planet is 1000 times that of Earth)
r₂ = 10r₁ (radius of the new planet is 10 times that of Earth)
Escape velocity on the new planet (vₑ₂) is:
vₑ₂ = √(2GM₂/r₂)
= √(2G(1000M₁)/(10r₁))
= √(200G(M₁/r₁))
= √200 × √(2GM₁/r₁)
= √200 × vₑ₁
Given vₑ₁ = 11.2 km/s:
vₑ₂ ≈ √200 × 11.2 km/s
≈ 112 km/s
- 16 days
- 8 days
- 4 days
- None of these
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Explanation
Kepler's law states:T² = T₀ × (R/R₀)³/²
Given:
R₀ = Rₑ + h₀ (geo-stationary satellite)
R = Rₑ + 4h₀ (new satellite)
T₀ = 24 hours (1 day)
R/R₀ = 5
T² ≈ 1 × 5³/² ≈ 8 days
کیپلر کے قوانین میں کہا گیا ہے کہ سورج کے بارے میں کسی بھی جسم کے وقت کی مدت کا مربع براہ راست _______ کے متناسب ہے؟
- 1/R³
- R³
- 1/R
- None of these
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Explanation
According to Kepler's third law:
The square of the time period (T²) of a planet.
The Sun is directly proportional to the cube of the semi-major axis (R³) of its orbit.
Mathematically, this can be expressed as:
T² ∝ R³
جب ایک پروٹون اور اینٹی پروٹون فنا ہوجاتا ہے تو ، توانائی کی رہائی ______ ہوتی ہے؟
- 3x10⁻⁶ J
- 3x10⁻¹⁰ J
- 3x10⁻⁸ J
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
When a proton and anti-proton annihilate, the energy release is equal to the sum of their rest mass energies.
The rest mass energy of a proton (or anti-proton) is approximately:
E = mc²
= (1.67 × 10⁻²⁷ kg) × (3 × 10⁸ m/s)²
≈ 1.5 × 10⁻¹⁰ J
Since both the proton and anti-proton annihilate, the total energy release is:
E_total = 2 × 1.5 × 10⁻¹⁰ J
≈ 3 × 10⁻¹⁰ J
- 8%
- 40%
- 36%
- None of these
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Explanation
Momentum (p) is proportional to velocity (v), while kinetic energy (KE) is proportional to v².
When momentum decreases by 20%, velocity decreases by 20%.
So, kinetic energy decreases by (1 - 0.8²) × 100% ≈ 36%.
- 2g
- g/3
- g/2
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
Let's denote the weight of the man in the stationary lift as W and the weight in the accelerating lift as W'.
We know that W' / W = 2/3.
When the lift is accelerating downward with acceleration 'a', the apparent weight (W') is given by:
W' = W - ma
where m is the mass of the man.
Since W' / W = 2/3, we can write:
(W - ma) / W = 2/3
Substitute W = mg (where g is the acceleration due to gravity):
(mg - ma) / mg = 2/3
Simplify:
g - a = (2/3)g
a = g - (2/3)g
a = (1/3)g
a = g/3
- 20°
- 35°
- 70°
- None of these
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Explanation
For maximum range, the angle of projection should be 45°.
However, since that's not an option, we need to find the angle closest to 45°.
Among the given options:
- - 35° is closer to 45° than 20°.
- - 60° is closer to 45° than 70°.
However, 35° is closer to 45° than 60°.
So, the correct answer is: 35°.
- 3V/4
- 4V
- 4V/3
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
Explanation
Since the smaller part becomes stationary, it means that the larger part will carry all the momentum.
Let's say the mass of the smaller part is m and the mass of the larger part is 3m.
Initial momentum = Final momentum
mV + 3mV = 3mV'
where V' is the velocity of the larger part.
Combine like terms:
4mV = 3mV'
Divide both sides by 3m:
V' = 4V/3
- 2h²
- h
- 2h
- None of these
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Explanation
When a man throws a ball to the maximum height (h), the initial velocity (v₀) is entirely vertical.
The maximum height (h) is given by:
h = v₀² / (2g)
where g is the acceleration due to gravity.
Now, when the man throws the same ball to the maximum horizontal distance, the initial velocity (v₀) is entirely horizontal.
The maximum horizontal distance (R) is given by:
R = v₀² / g
Substituting the expression for v₀² from the first equation:
R = 2h