Roots Of X² - 5x + 6 = 0?

Roots of x² - 5x + 6 = 0?

x = 2, -3
x = -2, 3
x = 2, 3
None of these

Explanation

x² - 5x + 6 = 0

Factor it: Find 2 numbers that multiply to 6 and add to -5 → -2 and -3

x² - 2x - 3x + 6 = 0

x(x - 2) - 3(x - 2) = 0

(x - 2)(x - 3) = 0

So x - 2 = 0 → x = 2

Or x - 3 = 0 → x = 3

Last verified on 09-05-2026

Related MCQs

1/x3 +1 =(A/x+1 ) + (Bx + C/ x2-x+c) find the value of A is?

1
1/3
-1/3
0

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Explanation

Given:

1/x ^{3} + 1 = A/ x + 1 + B x + C/ x ^{2} - x + 1

Since:

x^{3} + 1 = (x + 1) (x^{2} - x + 1)

Multiplying both sides by: $(x + 1) (x^{2} - x + 1)$ :

1 = A (x^{2} - x + 1) + (B x + C) (x + 1)

Expanding:

1 = (A + B) x^{2} + (- A + B + C) x + (A + C)

Comparing coefficients:

- A + B + C = 0

A + C = 1

A+B=0

B = - A

From $A + C = 1$ :

C = 1 - A

Substitute into the second equation:

- A - A + (1 - A) = 0

1 - 3 A = 0

A =1/ 3

Last updated on 23-07-2026 by NA

Evaluate (1/3)+(1/4)=?

5/12
7/12
4/7
1/ 12

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Simplify (60)² = ? × 72

3600
3528
0.02
50

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If a > b > 0, then?

a > b
a < b
a = b
None of these

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