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If x² - px + 110 has factors differing by 1, then p equals?
  1. 23
  2. 22
  3. 21
  4. None of these
Explanation

Let the factors be (x - n) and (x - n - 1).

Multiply: (x - n)(x - n - 1) = x^2 - (2n + 1)x + n(n + 1).

Set n(n + 1) = 110, which gives n = 10.

Then p = 2n + 1 = 21.


Last verified on 25-05-2026

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