Maclaurin’s series expansion of cosx is ______?
- cosx = 1 + x²/2!+x⁴/4!-x⁶/6! + ...
- cosx = 1 - x²/2!+x⁴/4!-x⁶/6! + ...
- cosx = 1 - x²/2!+x⁴/4!-x⁶/6! - ...
- None of these
Explanation
The Maclaurin series expansion of cos(x) is derived from its Taylor series expansion around x = 0:
cos(x) = 1 - x²/2! + x⁴/4! - x⁶/6! + ...
This series alternates signs and involves even powers of x, with factorials in the denominators.
The answer is cosx = 1 - x²/2! + x⁴/4! - x⁶/6! + ...
Related MCQs
- (x+5)(x−4)/(x−2)(x+2)
- x+5/x+2
- x−4/x−2
- x+5/x−2
اس سوال کو وضاحت کے ساتھ پڑھیں
- 20
- 25
- 30
- 35
اس سوال کو وضاحت کے ساتھ پڑھیں
