How many different 4-student committees can be chosen from A panel of 12 students?
- 11880
- 236
- 495
- 1980
Explanation
We need to choose a 4-student committee from a panel of 12 students. This is a combination problem, as the order of selection doesn't matter. We can use the combination formula:
C(n, k) = n! / (k!(n-k)!)
where n is the total number of students (12), k is the number of students to be chosen (4), and ! denotes the factorial function.
C(12, 4) = 12! / (4!(12-4)!)
= 12! / (4!8!)
= (12 × 11 × 10 × 9) / (4 × 3 × 2 × 1)
= 495
So, there are 495 different ways to choose a 4-student committee from a panel of 12 students.
Related MCQs
- 3/5, 1/2, 2/3, 3/4
- 1/2, 3/5, 2/3, 3/4
- 1/2, 2/3, 3/5, 3/4
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 1/3
- 1/4
- 1/2
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 2,800
- 3,500
- 2,100
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 4/5
- 7/8
- 11/12
- 5/6
اس سوال کو وضاحت کے ساتھ پڑھیں
