The order of differential equation x²dy + y²dx = 0 is?
- 3
- 2
- 1
- None
Explanation
The given differential equation is: x²dy + y²dx = 0
This is a first-order differential equation because it involves only the first derivative of y (i.e., dy) and not higher-order derivatives (such as d²y/dx²).
To see this more clearly, we can rewrite the equation as: dy/dx = -y²/x², which is a first-order differential equation in the form dy/dx = f(x,y).
Related MCQs
- {1}
- {-1}
- {0}
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- -72
- -60
- -48
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
