The differential form xdy - ydx/x^2 is equivalent to?
- d[ln(y/x)]
- d(y/x)
- d(ln(x/y))
- d(xy)
Explanation
The given differential form can be rewritten as:
xdy - ydx/x^2 = d(y/x) - (y/x^2)dx
Using the quotient rule for derivatives, we can simplify this to:
d(y/x) - (y/x^2)dx = d(ln(y/x))
Related MCQs
- 2x² + 4 = 9x
- 2x² + 9 = 4x
- 2x² + 9 = 4x
- x² + 4 = 9x
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