The length of the rectangle exceeds its breadth by 4m. If the perimeter of a rectangle is 84m, then the length and breadth of a rectangle is ________?
- L = 23, W = 19
- L = 19m, W = 23m
- L = 23m, W = 19m
- L = 4m, W = 84m
Explanation
Let's denote the length of the rectangle as L and the breadth as B.
According to the problem, the length exceeds the breadth by 4m, which can be expressed as L = B + 4.
The perimeter of a rectangle is calculated by adding the lengths of all its sides.
P = 2L + 2B.
We are given that the perimeter of the rectangle is 84m
2L + 2B = 84
Substituting L = B + 4 into the equation, we have:
2(B + 4) + 2B = 84
Simplifying the equation:
2B + 8 + 2B = 84
4B + 8 = 84
4B = 76
B = 19
Now, substitute the value of B back into L = B + 4:
L = 19 + 4
L = 23
Therefore, the length of the rectangle is 23m and the breadth is 19m.
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