Chef selects two sets of ingredients Set 1 and Set 2 for cooking, choosing from seven ingredients T, U, V, W, X, Y, and Z. Set 1 will contain four of the ingredients, and Set 2 will contain the other three ingredients. The Chef must select the ingredients

Explanation

 Chef selects two sets of ingredients Set 1 and Set 2 for cooking, choosing from seven ingredients T, U, V, W, X, Y, and Z. Set 1 will contain four of the ingredients, and Set 2 will contain the other three ingredients. The Chef must select the ingredients for each set according to the following restrictions:

T cannot be in the same set as U.

If X is in Set 2, Z must also be in Set 2.

If Z is in set 1, W must also be in Set 2.

Question:

If T and Z are in Set 2, any of the following ingredients can also be in Set 2 except:

A. X

B. Y

C. U

D. V

Question:

If Z is in Set 1, which of the following must be true?

A. U is in the same set as v

B. W is in the same set as Y

C. T is in set 1

D. V is in set 2

Question:

If X is in Set 2, which of the following must be true?

A. Y is in the same set as Z

B. T is in set 2

C. U is in Set 2

D. W is in set 1

ND5-07-2023

Solution

T and Z are in the same set like 2 then according to the given restriction there is only U which cannot be in same set as T so the first answer you have selected is wrong its U 1) U 2) V is in set 2 ( because V cannot be put in set 1 with Z,W,T/U,X) here Z,W,X should be fixed according to the given restriction. If you put X in set 2 then Z should also be in set 2 so the permanent member of set one according to question 2 is Set 1 ( Z,W,T/U,X) set 2 : ( U,Y,T/U) Question 3) If X is in set 2 then Z must also be in set 2. furthermore, there will be T/U in the set 2. and no more members because set 2 only contains 3 members. Example, set 1 : T/U, V,W,Y set 2 : X,Z,T/U A) condition 1: Y is in the same set as Z, which cannot be true b) T is in set 2, yes but T can be in set 1, so it is not the condition that must be true. c) U is in set 2, yes again U can be in set 1 so it again doesnt meet the "must be true condition" d) w is in set 1, yes this is correct, because if we put w in set 2 then we have to put T and U together which breaks the rule. mostly importantly there should be only 3 members in set 2. so W should be in set 1 along with T or U, V, Y. correct answer is D) W is in set 1

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