A street hawker sells two types of newspapers one for Rs. 25 and the other for Rs. 40. If she sold 100 newspapers for Rs. 2800. The newspapers she sold at Rs. 25 are?
- 80
- 85
- 90
- 5
Explanation
Let x be newspapers sold at Rs. 25, y be sold at Rs. 40x + y = 100 ... (1)
25x + 40y = 2800 ... (2)
From (1), y = 100-x
Put in (2):
25x + 40(100-x) = 2800
25x + 4000 - 40x = 2800
-15x = -1200
x = 80
Last verified on 07-03-2026
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