Three dice (each having six faces with each face having one number from 1 to 6) are rolled. What is the number of possible outcomes such that at least one dice shows the number 2?
- 36
- 81
- 91
- 116
Explanation
91
Hence, total number of ways =(3×5×5)+(3×5)+1=91.
Related MCQs
- 21, 22, 23, 24
- 22, 23, 24, 25
- 23, 24, 25, 26
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 3/5, 1/2, 2/3, 3/4
- 1/2, 3/5, 2/3, 3/4
- 1/2, 2/3, 3/5, 3/4
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 1/3
- 1/4
- 1/2
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 2,800
- 3,500
- 2,100
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- 4/5
- 7/8
- 11/12
- 5/6
اس سوال کو وضاحت کے ساتھ پڑھیں
