1/x3 +1 =(A/x+1 ) + (Bx + C/ X2-x+c) Find The Value Of A Is?

1/x3 +1 =(A/x+1 ) + (Bx + C/ x2-x+c) find the value of A is?

1
1/3
-1/3
0

Explanation

Given:

1/x ^{3} + 1 = A/ x + 1 + B x + C/ x ^{2} - x + 1

Since:

x^{3} + 1 = (x + 1) (x^{2} - x + 1)

Multiplying both sides by: $(x + 1) (x^{2} - x + 1)$ :

1 = A (x^{2} - x + 1) + (B x + C) (x + 1)

Expanding:

1 = (A + B) x^{2} + (- A + B + C) x + (A + C)

Comparing coefficients:

- A + B + C = 0

A + C = 1

A+B=0

B = - A

From $A + C = 1$ :

C = 1 - A

Substitute into the second equation:

- A - A + (1 - A) = 0

1 - 3 A = 0

A =1/ 3

Last updated on 23-07-2026 by NA

Related MCQs

1/x3 +1 =(A/x+1 ) + (Bx + C/ x2-x+c) find the value of A is?

1
1/3
-1/3
0

اس سوال کو وضاحت کے ساتھ پڑھیں

Explanation

Given:

1/x ^{3} + 1 = A/ x + 1 + B x + C/ x ^{2} - x + 1

Since:

x^{3} + 1 = (x + 1) (x^{2} - x + 1)

Multiplying both sides by: $(x + 1) (x^{2} - x + 1)$ :

1 = A (x^{2} - x + 1) + (B x + C) (x + 1)

Expanding:

1 = (A + B) x^{2} + (- A + B + C) x + (A + C)

Comparing coefficients:

- A + B + C = 0

A + C = 1

A+B=0

B = - A

From $A + C = 1$ :

C = 1 - A

Substitute into the second equation:

- A - A + (1 - A) = 0

1 - 3 A = 0

A =1/ 3

Last updated on 23-07-2026 by NA

Evaluate (1/3)+(1/4)=?

5/12
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4/7
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3600
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