Find the smallest number that, when divided by 8, 10, 20, and 30, leaves a remainder of 5 in each case.
- 120
- 125
- 240
- None of these
Explanation
LCM of 8, 10, 20, and 30 = 120.
Required number = LCM + remainder
= 120 + 5
= 125
Last verified on 09-10-2026
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