4^(2n+3) = 8^(n+5)?
- 9
- 7
- 8
- None of these
Explanation
Let's solve the equation:
4^(2n+3) = 8^(n+5)
Expressing both sides with base 2:
(2^2)^(2n+3) = (2^3)^(n+5)
2^(4n+6) = 2^(3n+15)
Equating exponents:
4n + 6 = 3n + 15
4n - 3n = 15 - 6
n = 9
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