If Point A Is (4, –1) And Point B Is (3, 5), What Is The Square Of The Distance AB² Between Them? - Testpoint

Testpoint Whatsapp group

Testpoint Whatsapp group

If point A is (4, –1) and point B is (3, 5), what is the square of the distance AB² between them?

26
37
136
121

Explanation

To find the square of the distance between two points $A(x_1, y_1)$ and $B (x_{2}, y_{2})$ :

$A B^^{2} = (x_{2} - x_{1})^^{2} + (y_{2} - y_{1})^^{2}$ $= (3 - 4)^2 + (5 - (-1))^2 = (-1)^2 + (6)^2 = 1 + 36 = 37$

$= (- 1)^^{2} + (6)^^{2}$

$= 1 + 36$

$= 37$

Related MCQs

Find the value of x: 27 : 72 :: x : 9 ?

3
3.375
4
4.5

اس سوال کو وضاحت کے ساتھ پڑھیں

Find the number which when added to itself 13 times, gives 112?

8
9
10
11

اس سوال کو وضاحت کے ساتھ پڑھیں

x² = y³ then x²ᶻ = y⁹, find z = ?

1
2
3
None of these

اس سوال کو وضاحت کے ساتھ پڑھیں

The solution set of (x-1)(x+5)=0 is?

{1,5}
{-1,-5}
{1,-5}
{-1,5}

اس سوال کو وضاحت کے ساتھ پڑھیں

If the value of the y-coordinate is zero, then which statement is correct?

The point will always lie on the y-axis.
The point will always lie on the x-axis.
The point will always lie in the first quadrant.
None of these

اس سوال کو وضاحت کے ساتھ پڑھیں

Test Point Whatsapp Channel

All Rights Reserved © TestPointpk.com