If n is a natural number the 9^2n - 4^2n is always divisible by?
- 13
- 05
- Both A & B
- None of these
Explanation
5 (as 9^n - 4^n is a difference of two odd powers, which is always divisible by 5)
13 (as 9^n - 4^n can be rewritten as (13-4)^n - 4^n, which is always divisible by 13)
Related MCQs
- Bisection method
- Taylor's method
- Newton-Raphson method
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
- a + b
- a + bi
- ab + i
- None of these
اس سوال کو وضاحت کے ساتھ پڑھیں
