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If 625 is the sum of 5 consecutive odd integers, then what is the largest of these integers?
  1. 129
  2. 131
  3. 133
  4. None of these
Explanation

Let the 5 consecutive odd integers be:  

x, x+2, x+4, x+6, x+8

Sum = x + (x+2) + (x+4) + (x+6) + (x+8) = 625  

5x + 20 = 625  

5x = 605  

x = 121

So the integers are: 121, 123, 125, 127, 129

Largest = 129


Last verified on 09-06-2026

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