If a^2 + b^2 = 8 and (a-b)^2 = 4. What is the value of ab?
- 4
- 1
- 2
- 3
Explanation
Given:
a^2 + b^2 = 8 ... (Equation 1)
(a - b)^2 = 4
Expanding the left side of the equation: a^2 - 2ab + b^2 = 4
Now, substitute Equation 1 into this equation: 8 - 2ab = 4
Subtract 8 from both sides: -2ab = -4
Divide both sides by -2: ab = 2
So, the value of ab is 2.
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