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The average of 20 numbers is zero of them at the most, how many may be greater than zero?
  1. 1
  2. 10
  3. 19
  4. 20
Explanation

If the average of 20 numbers is zero, their total sum is zero.  


To maximize the number of values greater than zero,  

→ assume only one value is negative,  

→ and the sum of the 19 positive numbers is exactly cancelled by that one negative number.


So, at most 19 numbers can be greater than zero. 

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