The Value Of An Article Which Was Purchased 2 Years Ago, Depreciates At 12 % Per Annum. If Its Present Value Is Rs .9680, The Price At Which It Was Purchased Is?

The value of an article which was purchased 2 years ago, depreciates at 12 % per annum. If its present value is Rs .9680, the price at which it was purchased is?

12,500
10000
19000
18000

Explanation

Given, $A =$ Rs. $9680, T = 2$ years, $R = 12 %$
$∵ A = P (1 - \frac{R}{1 0 0})$
$9680 = P (1 - \frac{1 2}{1 0 0})^{2}$
$9680 = P (\frac{8 8}{1 0 0})^{2}$
$P = 9680 \times \frac{2 5}{2 2} \times \frac{2 5}{2 2}$
$=$ Rs. $12, 500$

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The value of an article which was purchased 2 years ago, depreciates at 12 % per annum. If its present value is Rs .9680, the price at which it was purchased is?

Explanation

Given, $A =$ Rs. $9680, T = 2$ years, $R = 12 %$
$∵ A = P (1 - \frac{R}{1 0 0})$
$9680 = P (1 - \frac{1 2}{1 0 0})^{2}$
$9680 = P (\frac{8 8}{1 0 0})^{2}$
$P = 9680 \times \frac{2 5}{2 2} \times \frac{2 5}{2 2}$
$=$ Rs. $12, 500$

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The value of an article which was purchased 2 years ago, depreciates at 12 % per annum. If its present value is Rs .9680, the price at which it was purchased is?

Explanation

Given, A= Rs.9680,T=2 years,R=12%∵A=P(1−100R​)9680=P(1−10012​)29680=P(10088​)2P=9680×2225​×2225​= Rs. 12,500

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Given, $A =$ Rs. $9680, T = 2$ years, $R = 12 %$
$∵ A = P (1 - \frac{R}{1 0 0})$
$9680 = P (1 - \frac{1 2}{1 0 0})^{2}$
$9680 = P (\frac{8 8}{1 0 0})^{2}$
$P = 9680 \times \frac{2 5}{2 2} \times \frac{2 5}{2 2}$
$=$ Rs. $12, 500$